bantuin dong pliss pke caranya juga ya

Diagonal Bujur Sangkar = s√2
Diagonal Persegi Panjang = √(p² + l²)

5. D = 5√2

6. L = 49 cm² → s = √49 = √(7)² = 7 cm  ...............D = 7√2 cm

[tex]\bold{7.\ D=s \sqrt{2} \to s= \frac{D}{ \sqrt{2} }= \frac{1}{2}D \sqrt{2}} \\ \\ s= \frac{1}{2} \times 8 \sqrt{2} = \bold{4 \sqrt{2}} \\ \\ \\ L=(4 \sqrt{2})^2 = 4^2 \times 2= \bold{32\ cm^2}[/tex]

[tex]\bold{8.\ D= \sqrt{p^2+l^2}} \\ \\ D = \sqrt{40^2+9^2} = \sqrt{1600+81}= \sqrt{1.681}= \bold{41} \\ \\ \bold{9.\ Perbandingan\ ukuran\ p:l=4:3 \to p= \frac{4}{3}.l} \\ \\ Substitusikan :\\ \\ Keliling=2(p+l) \\ \\ 140=2( \frac{4}{3}l+l) =2( \frac{7}{3}l) = \frac{14}{3}l \\ \\ l=140 \times \frac{3}{14} =10 \times 3=30\ m \\ \\ p= \frac{4}{3}.l= \frac{4}{3} \times 30=4 \times 10=40\ m \\ \\ D= \sqrt{40^2+30^2}= \sqrt{1.600+900}= \sqrt{2.500}= \bold {50\ m}[/tex]

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