Tolong di jawab ya,kalau visa

Semoga membantu ya :)

[tex]f(x) = \frac{3x + 2}{x + 3} \\ {f}^{ - 1} (x) = \frac{3x + 2}{x + 3} \\ y = \frac{3x + 2}{x + 3} \\ y(x + 3) = 3x + 2 \\ xy + 3y = 3x + 2 \\ xy - 3x = 2 - 3y \\ x(y - 3) = 2 - 3y \\ x = \frac{2 - 3y}{y - 3} \\ \\ maka \: hasil \: dari \: \\ {f}^{ - 1} (x) = \frac{2 - 3x}{x - 3} [/tex]