simpangan baku dari data 10,4,7,8,6 dan 13 adalah..

jawab

xi = 10, 4, 7, 8, 6,13
n = 6
∑xi = 10+4+7+8+6+13 = 48
X = 48/6 = 8

S² = ∑|X-xi|² / (n)
S² = [ (10-8)² +(4-8)² +(7-8)² +(8-8)² +(6-8)² +(13-8)²] / (6)
S² = ( 4 + 16 + 1 + 0+ 4+ 25) / (6)
S² = 50/6 = 8,33

simpangan baku = √s² = √8,33 = 2.89