lim┬(x→16)〖(4-√x)/(16x-x^2 )=⋯〗 (Clue: gunakan teorema L’Hopital)
Matematika
marisanlestarioy5l79
Pertanyaan
lim┬(x→16)〖(4-√x)/(16x-x^2 )=⋯〗
(Clue: gunakan teorema L’Hopital)
(Clue: gunakan teorema L’Hopital)
1 Jawaban
-
1. Jawaban Anonyme
jawab
lim (x -> 16) (4 - √x) / (16x - x²)
lim(x->16) ( - 1/(2√x) / (16 - 2x)
x= 16
= -1/ (2√16) / (16 - 2(16))
= - 1/8 / (16-32)
= - 1/ (8)(-16)
= 1/ 128