Tentukan nilai x Dan y A.24:(x+7)=16:10 B.(5x-2):72=18:27 C.8:10=(y+15):25 D.21:28=24:(3y-4)
Matematika
rido167
Pertanyaan
Tentukan nilai x Dan y
A.24:(x+7)=16:10
B.(5x-2):72=18:27
C.8:10=(y+15):25
D.21:28=24:(3y-4)
A.24:(x+7)=16:10
B.(5x-2):72=18:27
C.8:10=(y+15):25
D.21:28=24:(3y-4)
1 Jawaban
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1. Jawaban algebralover
[tex]\ A.\ \frac{24}{x+7}=\frac{16}{10}\\ \\24\times10=16(x+7)....kedua\ ruas\ dibagi\ dgn\ 4\\6\times10=4(x+7)\\4x+28=60\\x=(60-28)\div4\\x=32\div4\\x=8\\ \\ \\Soal\ B.\ \frac{5x-2}{72}= \frac{18}{27}\\ \\27(5x-2)=18\times72....kedua\ ruas\ dibagi\ dgn\ 9\\3(5x-2)=18\times 8\\15x-6=144\\x=(144+6)\div15\\x=150\div15\\x=10\\ \\ \\Soal\ C.\ \frac{8}{10}= \frac{y+15}{25}\\ \\10(y+15)=25\times8....kedua\ ruas\ dibagi\ dgn\ 5\\2(y+15)=5\times8\\2y+30=40\\y=(40-30)\div2\\y=10\div2\\y=5[/tex]
[tex]Soal\ D.\ \frac{21}{28}=\frac{24}{3y-4}\\ \\21(3y-4)=24\times28....kedua\ ruas\ dibagi\ dgn\ 7\\3(3y-4)=24\times4....kedua\ ruas\ dibagi\ dgn\ 3\\3y-4=8\times4 \\y=(32+4)\div3 \\ y=36\div3 \\ y=12[/tex]
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