diketahui suku banyak f(x)=4x³-x²+2x+5dan 9(x)=2x²+x-4 tent nilai f(a) jika a=9(1)

a= g(1) = 2(1)²+1-4
a= -1

f(x)=4x³-x²+2x+5
f(a) = f(-1) = 4(-1)³-(-1)²+2(-1)+5
= -4-1+(-2)+5
= -2