tolong jawab..............,..........

jawab

ΔABC siku siku di B
AB= x+1
BC = x+2
AC = x+ 3

AC² = AB² + BC²
(x+3)² = (x+1)²+(x+2)²
x² +6x +9 = x² + 2x +1 + x² + 4x + 4
x²+ 6x + 9 = 2x² +6x + 5
x² -2x²+6x - 6x + 9 - 5= 0
-x² + 4=0
x²=  4
x = 2
a)
AB = x+1 = 3
BC= x+2 = 4
AC= x + 3= 5

b) Keliling = AB+ BC + AC = 3 + 4 + 5= 12

c) Luas = 1/2 (AB)(BC) = 1/2 (3)(4) = 6