tolong bantuin dong

Soal No. 2

[tex]a.\ 2^6 \times 2^7=2^{6+7}=2^{13} \\ \\ b.\ (-3)^5\times(-3)\times(-3)^7=(-3)^{5+1+7}=(-3)^{13} \\ \\c.\ 5^6\times5^7\times5^9=5^{6+7+9}=5^{22} \\ \\ d.\ 3a^2\times3a^3=3^2\times a^{2+3}=9a^5 \\ \\ e.\ 10p\times2q^2\times8p^5=(10\times2\times8)\times p^{1+5}\times q^2=160\ p^6q^2[/tex]

Soal No. 3

[tex] a.\ \frac{2^4}{2^3}=2^{4-3}=2^1=2\\ \\b.\ \frac{(-5)^7\times(-5)^8}{(-5)^{10}}=(-5)^{7+8-10}=(-5)^5\\ \\c.\ 7:7=7^{(1-1)}=7^0=1\\ \\d.\ \frac{(-3)^{19}\times(-3)^{23}}{(-3)^{25}\times(-3)^{7}}= \frac{(-3)^{19+23}}{(-3)^{25+7}}= \frac{(-3)^{42}}{(-3)^{32}}=(-3)^{(42-32)}=(-3)^{10}\\ \\e.\ \frac{100q^{35}}{25q^{17}}= \frac{100}{25}\times q^{(35-17)}=4\ q^{18}\\ \\f.\ \frac{23b^8\times 24b^{11}}{46b^{13}}= \frac{23\times24}{46}\times b^{(8+11-13)}=\frac{23\times24}{23\times2}\times b^{(19-13)}=12\ b^6 [/tex]

***Semoga Terbantu***