Jadi kalo 5log 36 . 6log 1/8 . ½log √1/125 ?? Gimana??

Mata Pelajaran : Matematika Peminatan
Kelas : 10
Bab : 02 - Fungsi Logaritma



[tex] {}^{5} log(36) . {}^{6} log( \frac{1}{8} ) . {}^{ \frac{1}{2} } log( \sqrt{ \frac{1}{125} } ) \\ = {}^{5} log(6 {}^{2} ) . {}^{6} log(2 {}^{ - 3} ) . {}^{2 {}^{ - 1} } log(5 {}^{ - \frac{3}{2} } ) \\ = 2. {}^{5} log(6) \times ( - 3. {}^{6} log2) \times \frac{3}{2} \times {}^{2} log(5) \\ = - {}^{5} log(6) \times 3. {}^{6} log(2) \times 3. {}^{2} log(5) \\ = - \frac{ {}^{2} log(6) }{ {}^{2} log(5) } \times 3. {}^{6 } log(2) \times 3. {}^{2} log(5) \\ = - { }^{2} log(6) \times 3. {}^{6} log(2) \times 3 \\ = - 1 \times 3 {}^{2} \\ = - 9[/tex]