Matematika

Pertanyaan

tolong ya semoga berhasil
tolong ya semoga berhasil

1 Jawaban

  • segitiga 1 = alas = 10 , tinggi = 24
    p => c^2 = a^2+b^2
    p=> c^2 = 10^2 + 24^2
    p=> c = √(100+576)
    p=> c = √(676) = 26

    segitiga 2 = alas = 12, tinggi = 5
    p => c^2 = a^2+b^2
    p=> c^2 = 12^2 + 5^2
    p=> c = √(144+25)
    p=> c = √(169) = 13

    segitiga 3 = alas = 8, tinggi = 15
    p => c^2 = a^2+b^2
    p=> c^2 = 8^2 + 15^2
    p=> c = √(64+225)
    p=> c = √(289) = 17

    segitiga 4 = alas = 12, tinggi = 16
    p => c^2 = a^2+b^2
    p=> c^2 = 12^2 + 16^2
    p=> c = √(144+256)
    p=> c = √(400) = 20

    semoga membantu yaa:)