tolong ya semoga berhasil
Matematika
andre924
Pertanyaan
tolong ya semoga berhasil
1 Jawaban
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1. Jawaban LouiseTantri2008
segitiga 1 = alas = 10 , tinggi = 24
p => c^2 = a^2+b^2
p=> c^2 = 10^2 + 24^2
p=> c = √(100+576)
p=> c = √(676) = 26
segitiga 2 = alas = 12, tinggi = 5
p => c^2 = a^2+b^2
p=> c^2 = 12^2 + 5^2
p=> c = √(144+25)
p=> c = √(169) = 13
segitiga 3 = alas = 8, tinggi = 15
p => c^2 = a^2+b^2
p=> c^2 = 8^2 + 15^2
p=> c = √(64+225)
p=> c = √(289) = 17
segitiga 4 = alas = 12, tinggi = 16
p => c^2 = a^2+b^2
p=> c^2 = 12^2 + 16^2
p=> c = √(144+256)
p=> c = √(400) = 20
semoga membantu yaa:)