Matematika

Pertanyaan

akar 32 dikurang akar 2 ditambah akar 128 adalah<br />[tex] \sqrt{32 - \sqrt{2 + \sqrt{128 = } } } [/tex]<br />

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  • [tex] =\sqrt{32}- \sqrt{2}+ \sqrt{128} \\ \\ = \sqrt{(16\times2)} - \sqrt{2} + \sqrt{(64\times2)} \\ \\ = (\sqrt{4^2} \times \sqrt{2})- \sqrt{2}+( \sqrt{8^2}\times \sqrt{2}) \\ \\ =4 \sqrt{2}- \sqrt{2}+8 \sqrt{2} \\ \\ =(4-1+8) \sqrt{2} \\ \\ =11 \sqrt{2} [/tex]

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