Nilai dari (64) pangkat 2per3 + (1per4) pangkat -2 dibagi 8 pangkat 2per3

[tex] {64}^{ \frac{2}{3} } +( { \frac{1}{4} })^{ - 2} \div {8}^{ \frac{2}{3} } \\ = \sqrt[3]{ {64}^{2} } + {4}^{2} \div \sqrt[3]{ {8}^{2} } \\ = \sqrt[3]{128} + 8 \div \sqrt[3]{64} \\ = \sqrt[3]{ {4}^{3} \times 2} + 8 \div 4 \\ = \frac{4 \sqrt[3]{2} + 8}{4} \\ = 2 + \sqrt[3]{2} [/tex]