Nilai 2log1/9 . 3log √1/125 .5log√8
Matematika
Alfiannurhakim06
Pertanyaan
Nilai 2log1/9 . 3log √1/125 .5log√8
1 Jawaban
-
1. Jawaban Anonyme
angka depan dianggap basis
^2log3^-2 . ^3log5^(-3/2) . ^5log2^(3/2)
= -2(-3/2)(3/2).^2log3.^3log5.^5log2
= (9/2).^2log2
= 9/2