Ada yang bisa bantu saya gak, tolong kakak yg baik hati

Sisi Miring = M
Sisi Dihadapan Sudut = H
Sisi Berdampingan Sudut = D
Sudut = α

[tex]Sin\ \alpha= \frac{H}{M} \\ \\ Cos\ \alpha = \frac{D}{M} \\ \\ Tan\ \alpha = \frac{H}{D} [/tex]

Soal a.
Diketahui :
M = 4
H = y
D = x
α = 60°

[tex]Sin\ 60^0 = \frac{y}{4} \\ \\ y=4 \times Sin\ 60^0 \\ \\ y=4 \times \frac{1}{2} \sqrt{3} \\ \\ y=2 \sqrt{3} \\ \\ \\ Cos\ 60^0= \frac{x}{4} \\ \\ x=4 \times Cos\ 60^0\\ \\ x=4 \times \frac{1}{2} \\ \\ x=2[/tex]

Soal b.
Diketahui :
M = x + 2
H = y
D = 8
α = 30°

[tex]Cos\ 30^0= \frac{8}{(x+2)} \\ \\ \frac{1}{2} \sqrt{3}=\frac{8}{(x+2)} \\ \\x + 2=\frac{8}{\frac{1}{2} \sqrt{3}} \\ \\ x + 2=\frac{16}{ \sqrt{3}}\\ \\ x + 2=\frac{16}{ \sqrt{3}} \times\frac{\sqrt{3}}{ \sqrt{3}} \\ \\ x + 2=\frac{16}{ 3}\sqrt{3}\\ \\ x=5\frac{1}{ 3}\sqrt{3}-2[/tex]

[tex]Sin\ 30^0 = \frac{y}{\frac{16}{ 3}\sqrt{3}} \\ \\ y=\frac{16}{ 3}\sqrt{3} \times Sin\ 30^0 \\ \\ y=\frac{16}{ 3}\sqrt{3} \times \frac{1}{2} \\ \\ y=\frac{8}{ 3} \sqrt{3} =2\frac{2}{ 3} \sqrt{3}[/tex]

Soal c.
M= 5√2
H = y
D = x
α = 45°

[tex]Sin\ 45^0 = \frac{y}{5 \sqrt{2} } \\ \\ y=5 \sqrt{2} \times Sin\ 45^0 \\ \\ y=5 \sqrt{2} \times \frac{1}{2} \sqrt{2} \\ \\ y= \frac{5}{2} \times 2\\ \\ y= 5 \\ \\ \\ Cos\ 45^0= \frac{x}{5 \sqrt{2}} \\ \\x=5 \sqrt{2} \times Cos\ 45^0 \\ \\ x=5 \sqrt{2} \times \frac{1}{2}\sqrt{2} \\ \\ x= \frac{5}{2} \times 2\\ \\ x= 5[/tex]

Soal d.
M = y
H = x
D = 5
α = 60°

[tex]Cos\ 60^0= \frac{5}{y} \\ \\\frac{1}{2} = \frac{5}{y} \\ \\ y= 5 \times 2 \\ \\ y= 10\\ \\ \\ Sin\ 60^0 = \frac{x}{10} \\ \\ \frac{1}{2} \sqrt{3} = \frac{x}{10} \\ \\ x= \frac{10}{2} \times \sqrt{3} \\ \\ x= 5 \sqrt{3} [/tex]

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