Berapa luas limas ini?

Mapel : Matematika
Bab : Bangun Ruang

Diketahui :
- Sisi Alas (s)/Alas Sisi Tegak (as) = 10 cm
- Tinggi Limas (tl) = 12 cm

Ditanya :
- Luas Permukaan Limas (Lp) = ......?

Penyelesaian :
- Luas Alas (La) :
La = s²
La = (10 cm)²
La = 100 cm²

- Tinggi Sisi Tegak (ts) :
ts = √tl² + (s/as ÷ 2)²
ts = √12² + (10 ÷ 2)²
ts = √144 + 5²
ts = √144 + 25
ts = √169
ts = 13 cm

- Luas Sisi Tegak (Lst) :
Lst = 4 × ½ × as × ts
Lst = 2 × 10 cm × 13 cm
Lst = 10 cm × 26 cm
Lst = 260 cm²

- Luas Permukaan Limas (Lp) :
Lp = La + Lst
Lp = 100 cm² + 260 cm²
Lp = 360 cm²

Maaf Kalau Salah

t^2 = 12^2 + (1/2 × 10)^2
t^2 = 12^2 + 5^2
t^2 = 144 + 25
t^2 = 169
t = V169
t = 13 cm

L = s^2 + 4 × 1/2 × a × t
L = 10^2 + 2 × 10 × 13
L = 100 + 260
L = 360 cm^2