Kak tolong di bantu no 9,10

Soal No. 9
Menghitung nilai x menggunakan rumus segitiga phytagoras
Luas segitiga kecil = 25 cm²
L = s² ⇒ s = √L ⇒ s = √25 ⇒ s= 5 

Sisi Miring = x
Sisi Tegak = 15 cm
Sisi Alas = 15 + 5 = 20 cm

[tex]x= \sqrt{15^2 + 5^2} \\ \\ x= \sqrt{225+25} \\ \\ x= \sqrt{250} \\ \\ x=\sqrt{25 \times 10} \\ \\ x= \sqrt{25} \times \sqrt{10} \\ \\ x=5 \sqrt{10} \ cm [/tex]

Soal No. 10
AC = 40 cm
BC = 24 cm
CD = 25 cm

Mencari panjang AB

[tex]AB= \sqrt{(AC)^2-(BC)^2} \\ \\ AB= \sqrt{40^2-24^2} \\ \\ AB= \sqrt{1.600-576} \\ \\AB= \sqrt{1.024} \\ \\ AB=32\ cm [/tex]

Mencari panjang BD

[tex]BD= \sqrt{(CD)^2-(BC)^2} \\ \\ BD= \sqrt{25^2-24^2} \\ \\ BD= \sqrt{625-576} \\ \\BD= \sqrt{49} \\ \\ BD=7\ cm[/tex]

AD = AB - BD
AD = 32 cm - 7 cm
AD = 25 cm

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