Kak tolong di bantu no(6[b],7)

No. 6B
Mencari panjang BD

[tex]BD = \sqrt{(BC)^2+(CD)^2} \\ \\ BD= \sqrt{7^2+4^2} \\ \\ BD= \sqrt{49+16} \\ \\ BD= \sqrt{65} \\ \\ \\ AB= \sqrt{(BD)^2-(AD)^2} \\ \\ AB= \sqrt{( \sqrt{65})^2-6^2} \\ \\ AB= \sqrt{65-36} \\ \\ AB= \sqrt{29} [/tex]

No. 7
(PA)² + (PC)² = (PB)² + (PD)²

[tex]PA= \sqrt{(PB)^2 + (PD)^2-(PC)^2} \\ \\ PA=\sqrt{7^2 + 4^2-8^2} \\ \\ PA=\sqrt{49 + 16-64} \\ \\ PA=\sqrt{65-64} \\ \\ PA= \sqrt{1} \\ \\ PA=1 [/tex]

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