Diketahui sin a=1/2 tentukan nilai dari 1.sin2a 2.cos2a 3.tan2a

[tex] \sin(a) = \frac{1}{2} \\ \cos(a) = \frac{ \sqrt{3} }{2} \\ \tan(a) = \frac{ \sqrt{3} }{3} \\ \sin(2a) = 2 \sin(a) \cos(a) = 2 \times \frac{1}{2} \times \frac{ \sqrt{3} }{2} = \frac{ \sqrt{3} }{2} \\ \cos(2a) = {cos}^{2} a - {sin}^{2} a = \frac{3}{4} - \frac{1}{4} = \frac{1}{2} \\ \tan(2a)= \frac{2 \tan(a) }{1 - {tan}^{2}a } = \frac{ \frac{2 \sqrt{3} }{3} }{ \frac{2}{3} } = \sqrt{3} [/tex]