berapa gram 1,204.10 23 buah molekul co2? Ar=12,O=16

X = n × BA

keterangan :
X = Jumlah partikel/molekul/atom
n = mol
BA = Bilangan avogadro

Jawab :

1,2 × 10^23 = n × 6,02 × 10^23

n = gram/ Mr

Mr CO2 = 12 + ( 2 × 16 )
= 44

maka, n = gram/44

jadi, 1,2 × 10^23 = gram/44 × 6,02 × 10^23
52,8/6,02 = gram
massa CO2 = 8,77 gram