(ax+2) (x-b) = 3x²-10x-8
Matematika
ale69
Pertanyaan
(ax+2) (x-b) = 3x²-10x-8
1 Jawaban
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1. Jawaban ahreumlim
Materi : Operasi pada Aljabar
(ax + 2) (x - b) = 3x² - 10x - 8
ax² - abx + 2x - 2b = 3x² - 10x - 8
ax² - (ab - 2)x - 2b = 3x² - 10x - 8
diperoleh
a = 3
2b = 8
b = 4
ab - 2 = 10
ab = 12
(3)(4) = 12 → benar
jadi
a = 3
b = 4