keliling sebidang kebun 280 meter.jika panjang kebun=5/3×lebarnya berapa cm³ luas kebun tersebut

panjang (p) = 5/3 lebar (l)
Keliling (k) = 280 m
K = 2 (p + l)
280 = 2 (5/3 l + l)
280 / 2 = 5/3 l + 3/3 l
140 = 8/3 l
l = (140 × 3 ÷ 8)
l = 52,5 m

P = 5/3 (52,5) = 87,5 m

Luas = p × l = 52,5 × 87, 5 = 4593, 75 m²

bismillah

diketahui keliling : 280 meter
panjang = 5/3 x lebar
(panjang = p, lebar = l)

ditanya luas dalam cm²

jawab keliling = 2 x (p+l)
280 = 2 x ( 5/3. l + l)
280 = 2 x 1 5/3 . l = 2 x 8/3. l
280 = 16/3 . l
l = 280 : 16/3 = 280 x 3/16 = 52,5 m = 5250

p = 5/3 x 52,5 = 87,5 m = 8750

luas = p x l = 8750 x 5250= 45.937.500 cm²


semoga bermanfaat..
mohon koreksinyaa..