Matematika

Pertanyaan

( ⅛ ) ⅔ + ( 32 ) ³/5 - ( 0,01 ) -½

1 Jawaban

  • Kelas 9 Matematika
    Bab Akar dan Pangkat

    ^ = pangkat

    (1/8)^(2/3) + (32)^(3/5) - (0,01)^(-1/2)
    = (2^-3)^(2/3) + (2^5)^(3/5) - (10^-2)^(-1/2)
    = 2^-2 + 2^3 - 10^1
    = 1/4 + 8 - 10
    = 1/4 - 2
    = 1/4 - 8/4
    = -7/4
    = -1 3/4

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