Matematika

Pertanyaan

diketahui 4log 5 = p nilai 2log125 adalah

2 Jawaban

  • ⁴log5 = p
    2²log5 = p
    ½ ²log5 = p
    ²log5 = 2p

    ²log125
    = ²log5³
    = 3 ²log5
    = 3 (2p)
    = 6p
  • 4log 5 = p
    log 5 / log 4 = p
    log 5 / log 2^2 = p
    log 5 / 2.log 2 = p
    log 5 / log 2 = 2p
    2log 5 = 2p
    2log 125
    = 2log 5^3
    =3.2log 5
    = 3.2p
    = 6p

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