Solusi persamaan [tex] 5^{2x+1} = 10^{2x-1} [/tex] adalah... A.2㏒25 B.2㏒50 C.4㏒25 D.4㏒50 E.5㏒4 Tolong ya... plisss

log 5^(2x+1) = log 10^(2x-1)
(2x+1).log 5 = (2x-1).log 10
(2x+1).log 5 = (2x-1). log 5.2
(2x+1).log 5 = (2x-1) log 5 + (2x-1) log 2
2x.log 5 + log 5 = 2x.log 5 -log 5 + 2x.log 2 - log 2.
log 5 + log 5 = 2x.log 2 - log 2
log (5×5) = x.log 2^2 - log 2
log 25 + log 2 = x.log 4
log (25×2) = x.log 4
x = log 50/log 4
x = 4log 50...(D)