Matematika

Pertanyaan

DIK : p(x)=x²+ax+b jika nilai p(3)=-8 dan p(-2)=7

1 Jawaban

  • p(x) = x²+ax+b

    p(3) = 3² + 3a + b = -8
    9 + 3a + b = -8
    3a + b = -8-9
    3a + b = -17

    p(-2) = (-2)² + (-2)a + b = 7
    4 - 2a + b = 7
    -2a + b = 7-3
    -2a + b = 4

    3a + b = -17
    -2a + b = 4
    -------------------- -
    5a = -21
    a = -21/5

    -2a + b = 4
    -2(-21/5) + b = 4
    42/5 + b = 4
    b = 4 - 42/5
    b = 20/5 - 42/5
    b = -22/5

    p(x)=x²+ax+b
    p(x)=x² - 21/5x - 22/5

    semoga membantu ###

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