DIK : p(x)=x²+ax+b jika nilai p(3)=-8 dan p(-2)=7
Matematika
silvianacresia
Pertanyaan
DIK : p(x)=x²+ax+b jika nilai p(3)=-8 dan p(-2)=7
1 Jawaban
-
1. Jawaban bangilham
p(x) = x²+ax+b
p(3) = 3² + 3a + b = -8
9 + 3a + b = -8
3a + b = -8-9
3a + b = -17
p(-2) = (-2)² + (-2)a + b = 7
4 - 2a + b = 7
-2a + b = 7-3
-2a + b = 4
3a + b = -17
-2a + b = 4
-------------------- -
5a = -21
a = -21/5
-2a + b = 4
-2(-21/5) + b = 4
42/5 + b = 4
b = 4 - 42/5
b = 20/5 - 42/5
b = -22/5
p(x)=x²+ax+b
p(x)=x² - 21/5x - 22/5
semoga membantu ###