tolong di bantu yah besok di kumpul Thanks

5. B
6. C
7. B. 2b

semoga bisa membantu

5.)

Pake rumus :
[tex]a {}^{2} - b {}^{2} \\ =(a + b)(a - b)[/tex]
Jadi,
[tex]9x {}^{2} - 16y {}^{2} \\ =(3x + 4y)(3x - 4y)[/tex]

Jawabannya B.

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6.)

[tex] \frac{2}{3x} + \frac{3x + 2}{9x} \\ = \frac{2(9x) + 3x(3x + 2)}{3x(9x)} \\ = \frac{18x + 9x {}^{2} + 6x}{3x(9x) } \\ = \frac{24x + 9x {}^{2} }{3x(9x)} \\ = \frac{3x(8 + 3x)}{3x(9x)} \\ = \frac{8 + 3x}{9x} [/tex]

Jadi, Jawabannya C.

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7.)

[tex] \frac{3a}{4b} \div \frac{6a}{16b {}^{2} } \\ = \frac{3a}{4b} \ \times \frac{16b {}^{2}}{ 6a} \\ = \frac{4b}{2} \\ = 2b[/tex]

Jadi, Jawabannya B.