tentukan nilai y dengan teorama phytagoras

[tex]({4x})^{2} + ( {3x})^{2} = {20}^{2} \\ {16x}^{2} + {9x}^{2} = 400 \\ 25 {x}^{2} = 400 \\ {x}^{2} = \frac{400}{25} \\ x = \sqrt{16} \\ x = 4[/tex]