Tentukan nilai p dari : [tex] \sqrt[3]{ 3^{(p+3)} } = \frac{1}{ 81\sqrt{ 27^{(2-2p)} } } [/tex]

∛3^(p+3) = 1/(81√27^(2-2p)
3^ ((p+3)/3) = 1 / (3^4 x 3^3(2-2p)/2
3^((p+3)/3) = 1 / (3^ (4+3(1-p))
3^ ((p+3)/3) = 1/ 3^ (4+3 -3p)
(p+3)/3 = -(7 - 3p)
p + 3 = -3(7-3p)
p+3 = -21 + 9p
24 = 8p
p = 3