Tolong Jawab Yang nomor 1-5.Pake Caranya! no Asal!

1.) nilai n dari
n = (40% + ½) × 250

[tex]n = ( \frac{40}{100} + \frac{1}{2} ) \times 250 \\ n = \frac{9}{10 \div 10} \times (250 \div 10)\\ n = 9 \times 25 \\ n = 225 \\ \\ 2.) \: (0.25 + \frac{3}{5} ) + ( \frac{1}{6} \times \frac{75 \div 25}{100 \div 25}) \\ = (\frac{1}{4} + \frac{3}{5} ) + ( \frac{1}{6} \times \frac{3}{4} ) \\ = \frac{17}{20} + ( \frac{1 }{2} \times \frac{1}{4} ) \\ = \frac{17}{20} + \frac{1}{8} \\ = \frac{34 + 5}{40} \\ = \frac{39}{40} \\ atau \\ 0.98\\ \\ 3.) \: \frac{9}{16} \div 0.45 - \frac{30}{100} \times 1.2 \\ = \frac{9}{16} \div \frac{9}{20} - \frac{30}{100} \times \frac{6}{5} \\ = \frac{9}{16} \times \frac{20}{9} - \frac{6}{50} \times 3 \\ = \frac{1}{4} \times 5 - \frac{3}{25} \times 3 \\ = \frac{5}{4} - \frac{9}{25} \\ = \frac{89}{100} [/tex]
≈ 0,89

4.) Dik.
Perbandingan = 3 : 5
Total = 40 anak

→ Selisih siswa laki² dan siswa perempuan yaitu
[tex] = \frac{5 - 3}{3 + 5} \times 40 \\ = \frac{2}{8} \times 40 \\ = 10 \: anak \\ \\ [/tex]

5.) → Panjang sebenarnya
= 8 cm ÷ 1 / 700
= 8 cm × 700 / 1
= (5.600 ÷ 100) m
= 56 m

→ Lebar sebenarnya
= 6 cm ÷ 1 / 700
= 6 cm × 700 / 1
= (4.200 ÷ 100) m
= 42 m

→ Luas sebenarnya
= 56 m × 42 m
= 2.352 m²