tolong dijawab no 2.a&b 3.a dan 4.a&b besok dikumpulkan

jawab

2a.

(3³. 3⁵. 3⁴) /  (3⁶.3². 3³) =
= (3)³⁺⁵⁺⁴  / (3)⁶⁺²⁺³
= (3)¹²  / (3)¹¹
= (3)¹²⁻¹¹
= (3)¹
= (3)

2b.
[(a³.b²) /(b². a)]² =

= (a⁶.b⁴)/(b⁴.a²)
= a⁶⁻². b⁴⁻⁴
= a⁴ . b⁰
= a⁴ (1)
= a⁴

3)
(-a b²)⁰. c⁴ / c⁻³ =
= (1) c⁴/ c⁻³
= c⁴⁺³
= c⁷

4) a

(1/3)² / (1/2)³ =
= (1/9)/ (1/8)
= 1/9 x 8/1
= 8/9

4b)
(4/x)⁻⁵ /(2/x)³ =

= 4⁵. x⁵  /  2³. x⁻³
= (2²)⁵ . x⁵  /  2³. x⁻³
= (2)¹⁰. (2)⁻³ . (x)⁵. (x)³
= 2¹⁰⁻³. x⁵⁺³
= 2⁷. x⁸