Matematika

Pertanyaan

[tex] \int\limits^ \frac{ \pi }{2} _0cos^2 {x}sin {x} \, dx [/tex]

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  • jawab


    misal u = cos x
    du = - sin x dx
    sin x dx = - du

    ∫cos² x sin x dx = -∫u² du

    = -1/3 (cos x )](π/2 ,,,0)

     = - 1/3  [cos π/2 - cos 0]

    = -1/3 [0 -1]

    = 1/3

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