[tex] \int\limits^1_0( x^{2} +1)^1^02 {x} \, dx [/tex]

jawab


₀¹∫ 2x. (x² +1)¹⁰
u = x² + 1
x = 0 --> u = 1
x = 1 --> u = 2

u  = x² +1
du = 2x dx

₁²∫ u^10 du  

1/11 (u)¹¹ ]²₁

1/11 (2¹¹ - 1¹¹)

= 1/11 (2047)

= 186,1