Diketahui f(x)=x^2-2x+5 dan g(x)=2x-3,rumus fungsi(f ° g)(x)=

Fungsi

fg(x) = f [ g(x) ]

= x(2x-3)² - 2(2x-3) +5
= x(4x²- 12x + 9) - (4x - 6) + 5
= 4x³- 12x² + 9 - 4x + 6 + 5
= 4x³ - 12x² - 4x + 20

Maka , fg(x) = 4x³ - 12x² - 4x + 20

atau

[ fg(x) = 4x³- 12x² - 4x + 20 ] ÷ 4

fg(x) = x³ - 3x² - x + 5